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Calculate the heat capacity of a 25.0 g sample of copper, given that it was heated from 25°C to 50°C when it absorbed 209 J of heat. The specific heat capacity of copper is 0.385 J/g°C.

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To calculate the heat capacity of the copper sample, we can use the formula:q = mcTwhere q is the heat absorbed  in joules , m is the mass of the sample  in grams , c is the specific heat capacity of the substance  in J/gC , and T is the change in temperature  in C .We are given the following information:- mass of the sample  m  = 25.0 g- specific heat capacity of copper  c  = 0.385 J/gC- initial temperature  T1  = 25C- final temperature  T2  = 50C- heat absorbed  q  = 209 JFirst, we need to calculate the change in temperature  T :T = T2 - T1 = 50C - 25C = 25CNow, we can plug the given values into the formula:209 J =  25.0 g  0.385 J/gC  25C To find the heat capacity, we need to solve for mc:mc = q / Tmc = 209 J / 25Cmc = 8.36 J/CThe heat capacity of the 25.0 g sample of copper is 8.36 J/C.

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