To calculate the heat capacity of the ethanol, we can use the formula:q = mcTwhere q is the heat absorbed in Joules , m is the mass in grams , c is the specific heat in J/gC , and T is the change in temperature in C .We are given the following information:- mass m = 25 grams- specific heat c = 2.44 J/gC- initial temperature T1 = 25C- final temperature T2 = 35C- heat absorbed q = 150 JoulesFirst, let's calculate the change in temperature T :T = T2 - T1T = 35C - 25CT = 10CNow, we can plug the values into the formula:150 J = 25 g 2.44 J/gC 10C To solve for the heat capacity, we can divide both sides of the equation by the mass and the change in temperature:Heat capacity = 150 J / 25 g * 10C Heat capacity = 150 J / 250 gCHeat capacity = 0.6 J/gCThe heat capacity of the 25 grams of liquid ethanol at 25C when heated from 25C to 35C by absorbing 150 Joules of heat is 0.6 J/gC.