In the K2Cr2O7 compound, the oxidation state of each element can be determined as follows:1. Potassium K is in Group 1 of the periodic table, and its oxidation state is always +1.2. Oxygen O typically has an oxidation state of -2.Let's denote the oxidation state of chromium Cr as x. The overall charge of the K2Cr2O7 compound is neutral 0 . Therefore, we can set up an equation to find the oxidation state of chromium:2 K + 2 Cr + 7 O = 02 +1 + 2 x + 7 -2 = 02 + 2x - 14 = 02x = 12x = 6So, the oxidation state of chromium Cr in K2Cr2O7 is +6.