The oxidation state of the chromium atom in K2Cr2O7 is +6.To determine this, we can use the oxidation state rules and the fact that the sum of the oxidation states of all atoms in a compound must equal the overall charge of the compound.In K2Cr2O7, we have:1. Two potassium K atoms, each with an oxidation state of +1 as it is an alkali metal in Group 1 .2. Two chromium Cr atoms, with an unknown oxidation state, which we will represent as x.3. Seven oxygen O atoms, each with an oxidation state of -2 as it is a common oxidation state for oxygen .Now, we can set up an equation to find the oxidation state of chromium:2 +1 + 2 x + 7 -2 = 0 since the overall charge of the compound is neutral Solving for x:2 + 2x - 14 = 02x = 12x = +6So, the oxidation state of the chromium atom in K2Cr2O7 is +6.