To find the oxidation state of chromium in the compound K2Cr2O7, we can use the oxidation state rules and the fact that the sum of the oxidation states of all the atoms in a neutral compound is equal to zero.1. The oxidation state of potassium K is always +1.2. The oxidation state of oxygen O is usually -2.In K2Cr2O7, there are 2 potassium atoms, 2 chromium atoms, and 7 oxygen atoms. Let's set up an equation using the oxidation state rules:2 K + 2 Cr + 7 O = 0Now, we can plug in the oxidation states for potassium and oxygen:2 +1 + 2 Cr + 7 -2 = 0Simplify the equation:2 + 2 Cr - 14 = 0Now, solve for the oxidation state of chromium Cr :2 Cr = 12Cr = +6So, the oxidation state of chromium in the compound K2Cr2O7 is +6.