When propene oxide C3H6O reacts with hydrogen iodide HI in the presence of red phosphorus as a catalyst, the expected product is 2-iodopropanol C3H7IO . The reaction conditions typically involve heating the reactants in a solvent, such as ether or acetic acid, at a temperature around 60-80C.The reaction proceeds through the following steps:1. The red phosphorus catalyzes the formation of iodine I2 from HI.2. The iodine reacts with HI to form the reactive species, triiodide ion I3- .3. The triiodide ion attacks the epoxide ring of propene oxide, leading to ring opening and formation of 2-iodopropanol.Overall, the reaction can be represented as:C3H6O + HI C3H7IO