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What is the product formed when propene (CH2=CHCH3) reacts with HBr in the presence of peroxide as a catalyst?

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When propene  CH2=CHCH3  reacts with HBr in the presence of peroxide as a catalyst, the reaction follows a free radical mechanism, which is also known as an anti-Markovnikov addition. In this case, the bromine atom  Br  will attach to the less substituted carbon of the double bond, and the hydrogen atom  H  will attach to the more substituted carbon. The product formed in this reaction is 1-bromopropane  CH3CH2CH2Br .
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