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What is the standard free energy change for the following redox reaction at 298 K?Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)Given: E°(Cu2+/Cu) = 0.34 V and E°(Zn2+/Zn) = -0.76 V

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To calculate the standard free energy change  G  for the redox reaction, we first need to determine the standard cell potential  Ecell  for the reaction. The standard cell potential can be found by subtracting the standard reduction potential of the anode  Zn  from the standard reduction potential of the cathode  Cu :Ecell = E Cu/Cu  - E Zn/Zn Ecell = 0.34 V -  -0.76 V  = 1.10 VNow that we have the standard cell potential, we can calculate the standard free energy change using the following equation:G = -nFEcellwhere n is the number of moles of electrons transferred in the reaction  in this case, n = 2, as one mole of Zn loses 2 electrons and one mole of Cu gains 2 electrons , F is the Faraday's constant  96,485 C/mol , and Ecell is the standard cell potential.G = -2 * 96,485 C/mol * 1.10 VG = -212,267 J/molThe standard free energy change for the redox reaction at 298 K is -212,267 J/mol.

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