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What is the standard free energy change for the following redox reaction at 25°C?2Fe3+(aq) + Sn2+(aq) → 2Fe2+(aq) + Sn4+(aq) Given: E°(Fe3+/Fe2+) = 0.771 V E°(Sn4+/Sn2+) = 0.150 V R = 8.314 J/K•mol F = 96,485 C/mol

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To calculate the standard free energy change  G  for the redox reaction, we first need to determine the standard cell potential  Ecell  for the reaction. This can be done using the Nernst equation:Ecell = E cathode  - E anode In this reaction, Fe3+ is reduced to Fe2+  cathode  and Sn2+ is oxidized to Sn4+  anode . Therefore, we can plug in the given values:Ecell = 0.771 V - 0.150 V = 0.621 VNow, we can use the relationship between the standard cell potential and the standard free energy change:G = -nFEcellwhere n is the number of moles of electrons transferred in the reaction, F is the Faraday constant  96,485 C/mol , and Ecell is the standard cell potential.In this reaction, 2 moles of electrons are transferred  from Sn2+ to Fe3+ . So, n = 2.G = -2 * 96,485 C/mol * 0.621 VG = -119,923.77 J/molSince 1 V = 1 J/C, the units are consistent, and the standard free energy change for the reaction at 25C is:G  -119,924 J/mol

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