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What is the yield of 2,4-dichlorobenzoic acid formed when 10 grams of benzoic acid and excess chlorine gas are used in the synthesis, if the actual yield obtained is only 6.5 grams?

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To calculate the yield of 2,4-dichlorobenzoic acid, we need to first determine the theoretical yield and then compare it to the actual yield obtained.1. Calculate the moles of benzoic acid used:The molecular weight of benzoic acid  C7H6O2  is 122.12 g/mol.moles of benzoic acid =  mass of benzoic acid  /  molecular weight of benzoic acid moles of benzoic acid =  10 g  /  122.12 g/mol  = 0.0819 mol2. Determine the stoichiometry of the reaction:The balanced chemical equation for the reaction is:C7H6O2 + 2 Cl2  C7H4Cl2O2From the balanced equation, we can see that 1 mole of benzoic acid reacts with 2 moles of chlorine gas to produce 1 mole of 2,4-dichlorobenzoic acid.3. Calculate the theoretical yield of 2,4-dichlorobenzoic acid:Since we have excess chlorine gas, benzoic acid is the limiting reagent. Therefore, the moles of 2,4-dichlorobenzoic acid produced will be equal to the moles of benzoic acid used.moles of 2,4-dichlorobenzoic acid = 0.0819 molThe molecular weight of 2,4-dichlorobenzoic acid  C7H4Cl2O2  is 191.02 g/mol.theoretical yield of 2,4-dichlorobenzoic acid =  moles of 2,4-dichlorobenzoic acid  *  molecular weight of 2,4-dichlorobenzoic acid theoretical yield =  0.0819 mol  *  191.02 g/mol  = 15.64 g4. Calculate the percentage yield:percentage yield =  actual yield / theoretical yield  * 100percentage yield =  6.5 g / 15.64 g  * 100 = 41.56%The yield of 2,4-dichlorobenzoic acid formed in this synthesis is 41.56%.
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