To calculate the yield of 2,4,6-trinitrotoluene TNT from the given reaction, we need to determine the limiting reactant and use stoichiometry to find the theoretical yield. Then, we can compare the theoretical yield to the actual yield to determine the percentage yield.First, let's find the moles of each reactant:1. Toluene C7H8 has a density of 0.87 g/mL and a molar mass of 92.14 g/mol.500 mL of toluene = 500 mL * 0.87 g/mL = 435 gMoles of toluene = 435 g / 92.14 g/mol = 4.72 mol2. Nitric acid HNO3 has a density of 1.51 g/mL for a 65% solution and a molar mass of 63.01 g/mol.700 mL of 65% nitric acid = 700 mL * 1.51 g/mL * 0.65 = 682.95 gMoles of nitric acid = 682.95 g / 63.01 g/mol = 10.84 molNow, let's determine the limiting reactant using the stoichiometry of the reaction:The balanced chemical equation for the nitration of toluene to TNT is:C7H8 + 3 HNO3 C7H5N3O6 + 3 H2OFrom the balanced equation, we can see that 1 mole of toluene reacts with 3 moles of nitric acid to produce 1 mole of TNT.Moles of nitric acid required for complete reaction with toluene = 4.72 mol * 3 = 14.16 molSince we only have 10.84 mol of nitric acid, nitric acid is the limiting reactant.Now, let's calculate the theoretical yield of TNT:Moles of TNT = 10.84 mol nitric acid / 3 = 3.61 molThe molar mass of TNT C7H5N3O6 is 227.13 g/mol.Mass of TNT = 3.61 mol * 227.13 g/mol = 819.93 gThe theoretical yield of TNT is 819.93 g.However, the actual yield of the reaction depends on various factors such as reaction efficiency, side reactions, and product loss during purification. To determine the actual yield, you would need to perform the reaction and measure the mass of the obtained TNT. Then, you can calculate the percentage yield by dividing the actual yield by the theoretical yield and multiplying by 100.