Question

What is the standard enthalpy change for the fusion reaction of 10.0 grams of solid water (H2O) at 0°C into liquid water at 0°C, given the standard enthalpy of fusion for water is 6.01 kJ/mol?

Answer 1

To calculate the standard enthalpy change for the fusion reaction, we need to first determine the number of moles of water and then use the standard enthalpy of fusion.1. Calculate the number of moles of water:The molar mass of water  H2O  is 18.015 g/mol  1.008 g/mol for hydrogen and 15.999 g/mol for oxygen .moles of water = mass / molar massmoles of water = 10.0 g / 18.015 g/molmoles of water  0.555 moles2. Calculate the standard enthalpy change for the fusion reaction:Standard enthalpy change = moles of water  standard enthalpy of fusionStandard enthalpy change = 0.555 moles  6.01 kJ/molStandard enthalpy change  3.34 kJThe standard enthalpy change for the fusion reaction of 10.0 grams of solid water at 0C into liquid water at 0C is approximately 3.34 kJ.