Question

What is the standard enthalpy change for the fusion of 100 grams of ice at 0°C to liquid water at 0°C? Assume that the specific heat capacity of ice and water are 2.09 and 4.18 J/g·°C, respectively, and the enthalpy of fusion of ice is 6.01 kJ/mol.

Answer 1

To calculate the standard enthalpy change for the fusion of 100 grams of ice at 0C to liquid water at 0C, we need to determine the number of moles of ice and then use the enthalpy of fusion to find the total enthalpy change.First, we need to find the number of moles of ice. The molar mass of water  H2O  is 18.015 g/mol.Number of moles =  mass of ice  /  molar mass of water Number of moles = 100 g / 18.015 g/mol = 5.55 moles  rounded to two decimal places Now, we can use the enthalpy of fusion  6.01 kJ/mol  to find the total enthalpy change for the fusion of 5.55 moles of ice.Enthalpy change =  number of moles    enthalpy of fusion Enthalpy change = 5.55 moles  6.01 kJ/mol = 33.36 kJ  rounded to two decimal places The standard enthalpy change for the fusion of 100 grams of ice at 0C to liquid water at 0C is 33.36 kJ.