Question

What is the rate of polymerization of vinyl acetate if the initial concentration of initiator is 0.05 mol/L, the rate constant at the polymerization temperature is 0.04 s^-1, and the reaction temperature is 60°C?

Answer 1

To calculate the rate of polymerization, we can use the following equation:Rate = k  [Initiator]Where:Rate = rate of polymerizationk = rate constant  0.04 s^-1 [Initiator] = initial concentration of initiator  0.05 mol/L Now, we can plug in the values:Rate =  0.04 s^-1    0.05 mol/L Rate = 0.002 mol/ Ls So, the rate of polymerization of vinyl acetate at 60C with an initial concentration of initiator of 0.05 mol/L and a rate constant of 0.04 s^-1 is 0.002 mol/ Ls .