To calculate the maximum power output of a galvanic cell, we first need to determine the cell potential E_cell under the given conditions. We can use the Nernst equation to do this:E_cell = E_cell - RT/nF * ln Q where E_cell is the standard cell potential, R is the gas constant 8.314 J/molK , T is the temperature in Kelvin 25C = 298.15 K , n is the number of electrons transferred in the redox reaction, F is the Faraday constant 96485 C/mol , and Q is the reaction quotient.For a galvanic cell consisting of a zinc electrode and a copper electrode, the overall redox reaction is:Zn s + Cu2+ aq Zn2+ aq + Cu s The standard reduction potentials for the half-reactions are:Zn2+ + 2e- Zn s E = -0.76 VCu2+ + 2e- Cu s E = +0.34 VThe standard cell potential E_cell is the difference between the reduction potentials of the two half-reactions:E_cell = E_Cu - E_Zn = 0.34 V - -0.76 V = 1.10 VThe number of electrons transferred in the redox reaction n is 2. The reaction quotient Q can be calculated as:Q = [Zn2+]/[Cu2+] = 0.1 M / 0.01 M = 10Now we can plug these values into the Nernst equation:E_cell = 1.10 V - 8.314 J/molK * 298.15 K / 2 * 96485 C/mol * ln 10 E_cell 1.10 V - 0.0295 V = 1.0705 VThe maximum power output P_max can be calculated using the formula:P_max = E_cell^2 / 4 * R_cell However, we do not have the internal resistance R_cell of the galvanic cell. Without this information, we cannot calculate the maximum power output.