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What is the mass of 2,4-dinitrophenol that can be obtained from 5 grams of phenol and excess nitric acid using the preparation method to synthesize 2,4-dinitrophenol?

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To calculate the mass of 2,4-dinitrophenol that can be obtained from 5 grams of phenol, we need to use stoichiometry. First, we need to find the balanced chemical equation for the synthesis of 2,4-dinitrophenol from phenol and nitric acid.The balanced chemical equation is:C6H5OH  phenol  + 2 HNO3  nitric acid   C6H3N2O5  2,4-dinitrophenol  + 2 H2O  water Now, we need to find the molar masses of phenol and 2,4-dinitrophenol.Phenol  C6H5OH :  6  12.01  +  5  1.01  + 16.00 = 94.11 g/mol2,4-Dinitrophenol  C6H3N2O5 :  6  12.01  +  3  1.01  +  2  14.01  +  5  16.00  = 184.11 g/molNext, we need to convert the mass of phenol  5 grams  into moles:moles of phenol = mass of phenol / molar mass of phenolmoles of phenol = 5 g / 94.11 g/mol = 0.0531 molAccording to the balanced chemical equation, 1 mole of phenol reacts to produce 1 mole of 2,4-dinitrophenol. Therefore, the moles of 2,4-dinitrophenol produced will be the same as the moles of phenol used:moles of 2,4-dinitrophenol = 0.0531 molNow, we can convert the moles of 2,4-dinitrophenol into mass:mass of 2,4-dinitrophenol = moles of 2,4-dinitrophenol  molar mass of 2,4-dinitrophenolmass of 2,4-dinitrophenol = 0.0531 mol  184.11 g/mol = 9.77 gTherefore, the mass of 2,4-dinitrophenol that can be obtained from 5 grams of phenol and excess nitric acid is approximately 9.77 grams.
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