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What is the yield of 2,4-dinitrophenol obtained in the preparation of 2,4-dinitrophenol from phenol and nitric acid, given that 10 grams of phenol was used and a 95% yield was achieved?

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To calculate the yield of 2,4-dinitrophenol, we first need to determine the theoretical yield based on the stoichiometry of the reaction and then apply the percentage yield.The balanced chemical equation for the reaction is:C6H5OH  phenol  + 2 HNO3  nitric acid   C6H3N2O5  2,4-dinitrophenol  + 2 H2O  water From the balanced equation, we can see that 1 mole of phenol reacts with 2 moles of nitric acid to produce 1 mole of 2,4-dinitrophenol.First, we need to find the moles of phenol used in the reaction:Moles of phenol = mass of phenol / molar mass of phenolMoles of phenol = 10 g /  94.11 g/mol  = 0.1063 molSince 1 mole of phenol produces 1 mole of 2,4-dinitrophenol, the theoretical yield of 2,4-dinitrophenol is also 0.1063 mol.Now, we need to convert the moles of 2,4-dinitrophenol to grams:Mass of 2,4-dinitrophenol = moles of 2,4-dinitrophenol  molar mass of 2,4-dinitrophenolMass of 2,4-dinitrophenol = 0.1063 mol   184.11 g/mol  = 19.56 g  theoretical yield Finally, we apply the percentage yield to find the actual yield:Actual yield = theoretical yield  percentage yieldActual yield = 19.56 g  0.95 = 18.58 gSo, the yield of 2,4-dinitrophenol obtained in the preparation is 18.58 grams.
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