To calculate the heat released when 50 g of water freezes to ice at -10C, we need to consider two steps:1. Cooling the water from 0C to -10C2. Freezing the water at 0CFirst, let's calculate the moles of water:Molar mass of water H2O = 18.015 g/mol50 g / 18.015 g/mol = 2.776 moles of waterStep 1: Cooling the water from 0C to -10CSpecific heat capacity of ice = 2.09 J/gCMass of water = 50 gTemperature change = -10Cq1 heat released = mass x specific heat capacity x temperature changeq1 = 50 g x 2.09 J/gC x -10C = -1045 JStep 2: Freezing the water at 0CHeat of crystallization for water = 6.01 kJ/molq2 heat released = moles x heat of crystallizationq2 = 2.776 moles x 6.01 kJ/mol = 16.68 kJ = 16680 JTotal heat released q_total = q1 + q2q_total = -1045 J + 16680 J = 15635 JSo, 15,635 J 15.635 kJ of heat is released when 50 g of water freezes to ice at -10C.