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What is the heat of crystallization when 50 grams of water is frozen to form ice at a temperature of -10°C? (Assuming the heat capacity of water is 4.184 J/g°C and the heat of fusion of water is 6.01 kJ/mol)

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To calculate the heat of crystallization, we need to consider two steps: 1. Cooling the water from its initial temperature  0C  to the freezing point  0C .2. Freezing the water at 0C to form ice.Step 1: Cooling the water to 0CSince the water is already at 0C, there is no heat exchange in this step.Step 2: Freezing the water at 0C to form iceFirst, we need to determine the number of moles of water. The molar mass of water is 18.015 g/mol.moles of water =  50 g  /  18.015 g/mol  = 2.776 molesNow, we can calculate the heat of fusion  Q_fusion  using the heat of fusion of water  6.01 kJ/mol .Q_fusion =  2.776 moles  *  6.01 kJ/mol  = 16.682 kJTherefore, the heat of crystallization when 50 grams of water is frozen to form ice at a temperature of -10C is 16.682 kJ.

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