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If 2.50 moles of propane react with excess oxygen gas, how much heat is released at constant pressure if the enthalpy change of the reaction is -2044 kJ/mol?

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To calculate the heat released during the reaction, we can use the following formula:q = n  Hwhere q is the heat released, n is the number of moles of propane, and H is the enthalpy change of the reaction.Given:n = 2.50 molesH = -2044 kJ/molNow, we can plug these values into the formula:q =  2.50 moles    -2044 kJ/mol q = -5110 kJSo, 5110 kJ of heat is released during the reaction at constant pressure.

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