Question

A researcher is working on the desorption of a specific gas from a metal surface. The enthalpy of desorption for this process is -23.4 kJ/mol. If the researcher desorbs 0.75 moles of the gas, how much heat is released (or absorbed)?

Answer 1

To calculate the heat released or absorbed during the desorption process, we can use the following formula:q = n * Hwhere q is the heat released or absorbed, n is the number of moles, and H is the enthalpy of desorption.In this case, n = 0.75 moles and H = -23.4 kJ/mol.q = 0.75 moles *  -23.4 kJ/mol  = -17.55 kJSince the value of q is negative, it means that 17.55 kJ of heat is released during the desorption process.