To calculate the heat of neutralization, we first need to determine the balanced chemical equation for the reaction between sulfuric acid H2SO4 and sodium hydroxide NaOH . The balanced equation is:H2SO4 + 2NaOH Na2SO4 + 2H2ONow, we need to determine the number of moles of each reactant. We can do this using the given concentrations and volumes:moles of H2SO4 = concentration of H2SO4 volume of H2SO4 moles of H2SO4 = 2.0 mol/L 50 mL 1 L/1000 mL moles of H2SO4 = 0.1 molmoles of NaOH = concentration of NaOH volume of NaOH moles of NaOH = 2.0 mol/L 50 mL 1 L/1000 mL moles of NaOH = 0.1 molSince the stoichiometry of the reaction is 1:2 1 mol of H2SO4 reacts with 2 mol of NaOH , we can see that both reactants are present in stoichiometric amounts, so neither is in excess.Now, we can calculate the heat of neutralization. The heat of neutralization for a strong acid and a strong base is approximately -57.32 kJ/mol of water formed. In this reaction, 2 moles of water are formed for every mole of H2SO4 reacted.Heat of neutralization = moles of H2SO4 heat of neutralization per mole of water formed number of moles of water formed per mole of H2SO4 Heat of neutralization = 0.1 mol -57.32 kJ/mol 2 mol Heat of neutralization = -11.464 kJSo, the heat of neutralization of sulfuric acid with sodium hydroxide at constant pressure for the given reaction conditions is approximately -11.464 kJ.