Question

What is the equilibrium constant at a temperature of 298 K for the reaction 2NOCl(g) ⇌ 2NO(g) + Cl2(g) if the initial concentrations at equilibrium are [NOCl] = 0.200 M, [NO] = 0.0250 M, and [Cl2] = 0.0250 M?

Answer 1

To calculate the equilibrium constant  Kc  for the given reaction, we can use the expression:Kc = [NO]^2 * [Cl2] / [NOCl]^2The problem states that at equilibrium, the concentrations are [NOCl] = 0.200 M, [NO] = 0.0250 M, and [Cl2] = 0.0250 M. We can plug these values into the Kc expression:Kc =  0.0250 ^2 *  0.0250  /  0.200 ^2Kc = 0.000625 * 0.0250 / 0.0400Kc = 0.015625 / 0.0400Kc  0.390625So, the equilibrium constant  Kc  for the given reaction at 298 K is approximately 0.391.