Question

A student wants to find the equilibrium constant for the following reaction at a temperature of 298 K:2NO(g) + Cl2(g) ⇌ 2NOCl(g)The student measures the equilibrium concentrations to be [NO] = 0.050 M, [Cl2] = 0.025 M, and [NOCl] = 0.080 M. What is the equilibrium constant (Kc) for the reaction at this temperature?

Answer 1

To find the equilibrium constant  Kc  for the reaction, we can use the expression:Kc = [NOCl]^2 /  [NO]^2 * [Cl2] We are given the equilibrium concentrations as [NO] = 0.050 M, [Cl2] = 0.025 M, and [NOCl] = 0.080 M. Plugging these values into the expression, we get:Kc =  0.080 ^2 /   0.050 ^2 *  0.025  Kc = 0.0064 /  0.0025 * 0.025 Kc = 0.0064 / 0.0000625Kc  102.4Therefore, the equilibrium constant  Kc  for the reaction at 298 K is approximately 102.4.