To calculate the enthalpy of vaporization of benzene, we need to determine the number of moles of benzene in 100 grams and then use the given energy requirement to find the enthalpy of vaporization per mole.First, we need to find the molar mass of benzene C6H6 :C: 12.01 g/mol 6 carbon atoms H: 1.01 g/mol 6 hydrogen atoms Molar mass of benzene = 6 12.01 + 6 1.01 = 72.06 + 6.06 = 78.12 g/molNow, we can find the number of moles in 100 grams of benzene:moles = mass / molar mass = 100 g / 78.12 g/mol = 1.280 molesGiven that it requires 45.8 kJ/mol of energy to vaporize 100 grams of benzene, we can now find the enthalpy of vaporization per mole:Enthalpy of vaporization = Energy required / molesEnthalpy of vaporization = 45.8 kJ / 1.280 moles = 35.8 kJ/molSo, the enthalpy of vaporization of benzene is approximately 35.8 kJ/mol.