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What is the amount of energy required to vaporize 50 grams of water at its boiling point, given that the enthalpy of vaporization of water is 40.7 kJ/mol?

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To calculate the amount of energy required to vaporize 50 grams of water at its boiling point, we need to first determine the number of moles of water and then use the enthalpy of vaporization to find the energy.1. Calculate the number of moles of water:The molar mass of water  H2O  is 18.015 g/mol. moles of water = mass of water / molar mass of watermoles of water = 50 g / 18.015 g/molmoles of water  2.775 moles2. Calculate the energy required using the enthalpy of vaporization:Energy = moles of water  enthalpy of vaporizationEnergy = 2.775 moles  40.7 kJ/molEnergy  112.94 kJTherefore, the amount of energy required to vaporize 50 grams of water at its boiling point is approximately 112.94 kJ.
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