To calculate the electrical conductivity of the solution, we need to consider the contributions of each ion in the solution. The electrical conductivity can be calculated using the following equation: = ci * i where ci is the concentration of each ion in mol/L and i is the molar conductivity of each ion in S cm/mol .First, let's identify the ions and their concentrations in the solution:1. Sodium ion Na+ : 0.1 M from sodium chloride 2. Chloride ion Cl- : 0.1 M from sodium chloride 3. Potassium ion K+ : 0.2 M from potassium nitrate 4. Nitrate ion NO3- : 0.2 M from potassium nitrate Next, we need the molar conductivity values for each ion at 25 C. These values can be found in tables or literature. Here are the approximate values for each ion:1. Na+ = 50.1 S cm/mol2. Cl- = 76.3 S cm/mol3. K+ = 73.5 S cm/mol4. NO3- = 71.4 S cm/molNow, we can calculate the electrical conductivity using the equation mentioned above: = 0.1 M * 50.1 S cm/mol + 0.1 M * 76.3 S cm/mol + 0.2 M * 73.5 S cm/mol + 0.2 M * 71.4 S cm/mol = 5.01 S cm + 7.63 S cm + 14.7 S cm + 14.28 S cm = 41.62 S cmSince the cell constant is given as 1.0 cm-1, we can directly use the calculated value as the electrical conductivity of the solution:Electrical conductivity of the solution = 41.62 S/m