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What is the corrosion rate of a copper metal in a 0.1 M HCl solution at 25°C and atmospheric pressure if the electrode potential of the copper metal is -0.34 V and the current density is 0.35 mA/cm²?

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To calculate the corrosion rate of copper in a 0.1 M HCl solution, we can use Faraday's law of electrolysis. The formula for Faraday's law is:Corrosion rate  CR  =  i * M * n  /  F *  * A Where:i = current density  0.35 mA/cm M = molar mass of copper  63.546 g/mol n = number of electrons exchanged in the redox reaction  2 for copper, as Cu  Cu + 2e F = Faraday's constant  96,485 C/mol  = density of copper  8.96 g/cm A = area of the copper surface  1 cm First, we need to convert the current density from mA/cm to A/cm:0.35 mA/cm = 0.35 * 10^-3  A/cm = 3.5 * 10^-4  A/cmNow, we can plug in the values into the formula:CR =  3.5 * 10^-4  A/cm * 63.546 g/mol * 2  /  96,485 C/mol * 8.96 g/cm * 1 cm CR =  0.0445912 gmolC  /  865.416 Cgmol CR = 5.15 * 10^-5  cm/sTo convert the corrosion rate to a more common unit, such as mils per year  mpy , we can use the following conversion factor:1 cm/s = 3.170 * 10^7 mil/yearCR = 5.15 * 10^-5  cm/s * 3.170 * 10^7 mil/yearCR  1.63 mil/yearSo, the corrosion rate of copper in a 0.1 M HCl solution at 25C and atmospheric pressure with an electrode potential of -0.34 V and a current density of 0.35 mA/cm is approximately 1.63 mil/year.

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