0 votes
45 views
in ElectroChemistry by (390 points)
Calculate the corrosion rate of iron (Fe) in a galvanic couple with copper (Cu), given that the area of the iron electrode is 8 cm² and the current density is 0.6 mA/cm². The standard electrode potential of iron is -0.44 V and that of copper is +0.34 V.

1 Answer

0 votes
by (470 points)
To calculate the corrosion rate of iron in a galvanic couple with copper, we need to determine the mass loss rate of iron due to the galvanic corrosion. The corrosion rate can be calculated using Faraday's Law of Electrolysis:Corrosion rate =  i  A  M  /  n  F where:- i is the current density  0.6 mA/cm - A is the area of the iron electrode  8 cm - M is the molar mass of iron  55.85 g/mol - n is the number of electrons involved in the redox reaction  2 for iron, as it forms Fe ions - F is Faraday's constant  96,485 C/mol First, we need to convert the current density from mA/cm to A/cm:0.6 mA/cm = 0.6  10 A/cm = 0.0006 A/cmNow we can calculate the corrosion rate:Corrosion rate =  0.0006 A/cm  8 cm  55.85 g/mol  /  2  96,485 C/mol Corrosion rate =  0.02664 g/mol  /  192,970 C/mol Corrosion rate = 1.38  10 g/CTo find the corrosion rate in terms of mass loss per unit time, we need to multiply the corrosion rate by the total current  i  A :Total current = 0.0006 A/cm  8 cm = 0.0048 AMass loss rate = 1.38  10 g/C  0.0048 AMass loss rate = 6.62  10 g/sThe corrosion rate of iron in the galvanic couple with copper is approximately 6.62  10 g/s.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...