To balance the redox equation for the reaction between iron II chloride FeCl2 and potassium permanganate KMnO4 in acidic solution, we need to follow these steps:1. Write down the unbalanced equation:FeCl2 + KMnO4 FeCl3 + MnCl2 + KCl2. Separate the redox reaction into half-reactions:Oxidation half-reaction: Fe Fe + eReduction half-reaction: MnO + 8H + 5e Mn + 4HO3. Balance the half-reactions:Oxidation half-reaction: Fe Fe + e already balanced Reduction half-reaction: MnO + 8H + 5e Mn + 4HO already balanced 4. Equalize the number of electrons in both half-reactions:To do this, multiply the oxidation half-reaction by 5 and the reduction half-reaction by 1, so that both half-reactions have 5 electrons.5Fe 5Fe + 5eMnO + 8H + 5e Mn + 4HO5. Add the half-reactions and cancel out the electrons:5Fe + MnO + 8H 5Fe + Mn + 4HO6. Balance the charges by adding appropriate spectator ions:5FeCl2 + KMnO4 + 8HCl 5FeCl3 + MnCl2 + 4HO + KCl7. Check if the equation is balanced in terms of atoms and charges:5Fe + MnO + 8H + 5Cl 5Fe + Mn + 4HO + 5Cl + KThe balanced redox equation for the reaction between iron II chloride and potassium permanganate in acidic solution is:5FeCl2 + KMnO4 + 8HCl 5FeCl3 + MnCl2 + 4HO + KCl