To balance the redox equation for the reaction of potassium permanganate KMnO4 with iron II sulfate FeSO4 in acidic solution, we need to follow these steps:1. Write down the unbalanced equation:KMnO4 + FeSO4 -> MnSO4 + K2SO4 + Fe2 SO4 32. Separate the equation into half-reactions:Oxidation half-reaction: Fe^2+ -> Fe^3+Reduction half-reaction: MnO4^- -> Mn^2+3. Balance the atoms in each half-reaction:Oxidation half-reaction: Fe^2+ -> Fe^3+ + e^-Reduction half-reaction: MnO4^- + 8H^+ + 5e^- -> Mn^2+ + 4H2O4. Balance the electrons in both half-reactions:Multiply the oxidation half-reaction by 5 and the reduction half-reaction by 1 to balance the electrons:5 Fe^2+ -> Fe^3+ + e^- 1 MnO4^- + 8H^+ + 5e^- -> Mn^2+ + 4H2O 5. Add the half-reactions together and cancel out the electrons:5Fe^2+ + MnO4^- + 8H^+ -> 5Fe^3+ + Mn^2+ + 4H2O6. Balance the charges by adding appropriate spectator ions:5Fe^2+ + MnO4^- + 8H^+ + 5SO4^2- -> 5Fe^3+ + Mn^2+ + 4H2O + 5SO4^2- + 2K^+7. Combine the ions to form the balanced redox equation:5FeSO4 + KMnO4 + 8H2SO4 -> 5Fe2 SO4 3 + MnSO4 + K2SO4 + 4H2OSo, the balanced redox equation for the reaction of potassium permanganate with iron II sulfate in acidic solution is:5FeSO4 + KMnO4 + 8H2SO4 -> 5Fe2 SO4 3 + MnSO4 + K2SO4 + 4H2O