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What is the anodic Tafel slope for an electrochemical reaction where the current density increases by a factor of 10 as the overpotential increases from 0.1 V to 0.3 V? The exchange current density at the electrode is 1.0 x 10^-5 A/cm^2.

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The Tafel equation is used to describe the relationship between the overpotential    and the current density  j  in an electrochemical reaction. The anodic Tafel slope  ba  can be calculated using the following equation:ba =  RT  /  a * F where R is the gas constant  8.314 J/mol K , T is the temperature in Kelvin, a is the anodic charge transfer coefficient, and F is the Faraday constant  96485 C/mol .In this problem, we are given that the current density increases by a factor of 10 as the overpotential increases from 0.1 V to 0.3 V. We can use the Tafel equation to relate the overpotential and current density: = ba * log j / j0 where  is the overpotential, j is the current density, and j0 is the exchange current density.We can set up two equations for the two given overpotentials:0.1 V = ba * log j1 / j0 0.3 V = ba * log j2 / j0 Since the current density increases by a factor of 10, we can write j2 = 10 * j1. Now we can solve for ba:0.3 V = ba * log  10 * j1  / j0 0.1 V = ba * log j1 / j0 Divide the first equation by the second equation:3 = log  10 * j1  / j0  / log j1 / j0 Now, we can use the property of logarithms log a  / log b  = log a^1 / b^1  = log a / b :3 = log  10 * j1  / j1 Solve for j1:10 * j1 = j1^3j1^2 = 10Now, we can substitute j1 back into the Tafel equation:0.1 V = ba * log j1 / j0 0.1 V = ba * log  j1^2  /  j0 * j1  0.1 V = ba * log 10 / j0 Since j0 is given as 1.0 x 10^-5 A/cm^2:0.1 V = ba * log 10 /  1.0 x 10^-5  0.1 V = ba * log 10^6 Now, we can solve for ba:ba = 0.1 V / log 10^6 ba  0.1 V / 13.8ba  0.00725 V/decadeThe anodic Tafel slope for this electrochemical reaction is approximately 0.00725 V/decade.

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