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What is the anodic Tafel slope for the oxidation of zinc in a solution of 0.5 M NaCl at 25°C with a current density of 5 mA/cm2? The exchange current density value for the reaction is 2.5 x 10^-6 A/cm2.

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To calculate the anodic Tafel slope  ba  for the oxidation of zinc, we can use the Tafel equation: = ba * log i / i0 where  is the overpotential, i is the current density, and i0 is the exchange current density.First, we need to find the overpotential   . We can do this by rearranging the Tafel equation: = ba * log i / i0 ba =  / log i / i0 Given the current density  i  is 5 mA/cm  0.005 A/cm  and the exchange current density  i0  is 2.5 x 10^-6 A/cm, we can plug these values into the equation: = ba * log 0.005 / 2.5 x 10^-6 However, we don't have the value of overpotential    given in the problem. To find the anodic Tafel slope  ba , we need the overpotential value. If you can provide the overpotential value, we can calculate the anodic Tafel slope for the oxidation of zinc in the given solution.

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