Question

What is the standard enthalpy change for the sublimation of iodine, given that the enthalpy change of fusion for iodine is +15.3 kJ/mol and the enthalpy change of vaporization for iodine is +41.7 kJ/mol?

Answer 1

The standard enthalpy change for the sublimation of iodine can be calculated by adding the enthalpy change of fusion and the enthalpy change of vaporization. This is because sublimation is the process of a solid turning directly into a gas, which involves both fusion  solid to liquid  and vaporization  liquid to gas .H_sublimation = H_fusion + H_vaporizationGiven:H_fusion = +15.3 kJ/molH_vaporization = +41.7 kJ/molH_sublimation = 15.3 kJ/mol + 41.7 kJ/molH_sublimation = 57.0 kJ/molThe standard enthalpy change for the sublimation of iodine is +57.0 kJ/mol.