Question

What is the standard enthalpy change for sublimation of iodine, given that the heat of fusion of iodine is 15.4 kJ/mol and the heat of vaporization of iodine is 41 kJ/mol?

Answer 1

The standard enthalpy change for sublimation of iodine can be calculated by adding the heat of fusion and the heat of vaporization. Sublimation is the process of a solid turning directly into a gas, bypassing the liquid phase. In the case of iodine, this involves first melting the solid  heat of fusion  and then vaporizing the liquid  heat of vaporization .H_sublimation = H_fusion + H_vaporizationGiven the heat of fusion  H_fusion  is 15.4 kJ/mol and the heat of vaporization  H_vaporization  is 41 kJ/mol:H_sublimation = 15.4 kJ/mol + 41 kJ/molH_sublimation = 56.4 kJ/molSo, the standard enthalpy change for sublimation of iodine is 56.4 kJ/mol.