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Identify the reaction mechanism and the intermediate species involved in the formation of alcohol in the reaction between an alkene and water in the presence of a sulfuric acid catalyst.

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The reaction between an alkene and water in the presence of a sulfuric acid catalyst to form an alcohol is known as an acid-catalyzed hydration reaction. The reaction mechanism involves three main steps and proceeds through a carbocation intermediate species.1. Protonation of the alkene: In the first step, the alkene reacts with the sulfuric acid  H2SO4  to form a protonated alkene. The alkene acts as a nucleophile and attacks the proton  H+  from the sulfuric acid, resulting in the formation of a carbocation intermediate. This step is reversible.2. Nucleophilic attack by water: In the second step, the carbocation intermediate formed in the first step is attacked by a water molecule, which acts as a nucleophile. The oxygen atom in the water molecule donates a pair of electrons to the carbocation, forming a bond with the carbon atom. This results in the formation of an oxonium ion intermediate.3. Deprotonation: In the final step, the oxonium ion intermediate loses a proton  H+  to another water molecule or a bisulfate ion  HSO4-  from the sulfuric acid, resulting in the formation of the alcohol product and regenerating the acid catalyst.Overall, the reaction mechanism involves the formation of a carbocation intermediate and an oxonium ion intermediate, with the sulfuric acid catalyst playing a crucial role in the protonation and deprotonation steps.
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