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What is the balanced chemical equation for the preparation of 2-chloro-4-nitroaniline from aniline and chlorine gas? Show all the reactants, products, and their respective coefficients.

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The preparation of 2-chloro-4-nitroaniline from aniline and chlorine gas involves two main steps: nitration and chlorination. 1. Nitration of aniline:C6H7N + HNO3 -> C6H6N2O2 + H2OIn this step, aniline  C6H7N  reacts with nitric acid  HNO3  to form 4-nitroaniline  C6H6N2O2  and water  H2O .2. Chlorination of 4-nitroaniline:C6H6N2O2 + Cl2 -> C6H5ClN2O2 + HClIn this step, 4-nitroaniline  C6H6N2O2  reacts with chlorine gas  Cl2  to form 2-chloro-4-nitroaniline  C6H5ClN2O2  and hydrogen chloride  HCl .Overall balanced chemical equation:C6H7N + HNO3 + Cl2 -> C6H5ClN2O2 + H2O + HCl

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