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What is the specific mechanism and reaction conditions necessary for the preparation of 2,4-dinitrobenzoic acid from benzoic acid and nitric acid, and what intermediate products are formed during the process?

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The preparation of 2,4-dinitrobenzoic acid from benzoic acid and nitric acid involves a nitration reaction. The specific mechanism and reaction conditions are as follows:1. Reaction conditions:- Concentrated nitric acid  HNO3 - Concentrated sulfuric acid  H2SO4  as a catalyst- Temperature: 0-5C  ice bath  for the first nitration step, and around 50-60C for the second nitration step2. Mechanism:a  Formation of the nitronium ion  NO2+ :Concentrated H2SO4 protonates HNO3, forming the nitronium ion  NO2+  and bisulfate ion  HSO4- .HNO3 + H2SO4 -> NO2+ + HSO4- + H2Ob  First nitration step  formation of 4-nitrobenzoic acid :The nitronium ion  NO2+  acts as an electrophile and attacks the aromatic ring of benzoic acid, forming an intermediate arenium ion. The most favorable position for the first nitration is the para position  4-position  due to the electron-withdrawing nature of the carboxyl group  -COOH  in benzoic acid. The intermediate then loses a proton to regenerate the aromatic ring, resulting in the formation of 4-nitrobenzoic acid.c  Second nitration step  formation of 2,4-dinitrobenzoic acid :The 4-nitrobenzoic acid undergoes a second nitration reaction, with the nitronium ion attacking the ortho position  2-position  relative to the carboxyl group. This forms an intermediate arenium ion, which then loses a proton to regenerate the aromatic ring, resulting in the formation of 2,4-dinitrobenzoic acid.3. Intermediate products:- 4-nitrobenzoic acid- Arenium ion intermediates during the nitration stepsOverall, the reaction can be summarized as:C6H5COOH  benzoic acid  + 2 HNO3  nitric acid  -> C6H3 NO2 2COOH  2,4-dinitrobenzoic acid  + 2 H2O  water

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