The Lewis structure of the molecule SiO2 silicon dioxide is as follows:1. Count the total number of valence electrons: Silicon Si has 4 valence electrons, and Oxygen O has 6 valence electrons. Since there are two oxygen atoms, the total number of valence electrons is 4 + 2 6 = 16.2. Place the least electronegative atom Si in the center and surround it with the more electronegative atoms O . O | Si | O3. Connect the atoms with single bonds. Each bond represents 2 electrons, so we have used 4 electrons so far.4. Distribute the remaining electrons 12 as lone pairs on the surrounding oxygen atoms to satisfy the octet rule. Each oxygen atom will have 3 lone pairs 6 electrons . O : | : Si : | : O5. Check if the central atom Si has a complete octet. In this case, Si has only 4 electrons from the two single bonds. To complete the octet, we need to form double bonds between Si and each O atom. O : || : Si : || : ONow, the Lewis structure of SiO2 is complete, with each atom having a full octet of electrons.