The given balanced chemical equation is incorrect for the reaction between NaOH and HCl. The correct balanced chemical equation for the reaction between NaOH and HCl is:NaOH aq + HCl aq NaCl aq + H2O l Now, we can proceed to find the mass of NaOH needed to react completely with 25.0 g of HCl.First, we need to find the moles of HCl:Moles of HCl = mass of HCl / molar mass of HClMolar mass of HCl = 1 H + 35.5 Cl = 36.5 g/molMoles of HCl = 25.0 g / 36.5 g/mol = 0.6849 molFrom the balanced equation, we can see that the mole ratio between NaOH and HCl is 1:1. Therefore, the moles of NaOH needed is equal to the moles of HCl.Moles of NaOH = 0.6849 molNow, we can find the mass of NaOH:Mass of NaOH = moles of NaOH molar mass of NaOHMolar mass of NaOH = 23 Na + 16 O + 1 H = 40 g/molMass of NaOH = 0.6849 mol 40 g/mol = 27.4 gSo, 27.4 grams of NaOH is needed to react completely with 25.0 g of HCl.