A chemistry student needs to determine the concentration of a sulfuric acid solution by titrating 25.0 mL of the acid with 0.1000 M sodium hydroxide. The reaction between the two substances is H2SO4 + 2NaOH → Na2SO4 + 2H2O. If it takes 35.0 mL of the sodium hydroxide solution to fully neutralize the sulfuric acid, what is the concentration of the sulfuric acid solution in moles per liter (M)?

Question

A chemistry student needs to determine the concentration of a sulfuric acid solution by titrating 25.0 mL of the acid with 0.1000 M sodium hydroxide. The reaction between the two substances is H2SO4 + 2NaOH → Na2SO4 + 2H2O. If it takes 35.0 mL of the sodium hydroxide solution to fully neutralize the sulfuric a

Answer 1

To determine the concentration of the sulfuric acid solution, we can use the balanced chemical equation and the concept of stoichiometry. The balanced equation is:H2SO4 + 2NaOH  Na2SO4 + 2H2OFrom the balanced equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.First, we need to find the moles of NaOH used in the titration:moles of NaOH =  volume of NaOH in L    concentration of NaOH in M moles of NaOH =  35.0 mL   1 L / 1000 mL    0.1000 Mmoles of NaOH = 0.0350 L  0.1000 Mmoles of NaOH = 0.00350 molesNow, we can use the stoichiometry from the balanced equation to find the moles of H2SO4:moles of H2SO4 =  moles of NaOH    1 mole H2SO4 / 2 moles NaOH moles of H2SO4 = 0.00350 moles   1/2 moles of H2SO4 = 0.00175 molesFinally, we can find the concentration of the sulfuric acid solution:concentration of H2SO4 =  moles of H2SO4  /  volume of H2SO4 in L concentration of H2SO4 = 0.00175 moles /  25.0 mL   1 L / 1000 mL  concentration of H2SO4 = 0.00175 moles / 0.0250 Lconcentration of H2SO4 = 0.0700 MSo, the concentration of the sulfuric acid solution is 0.0700 M.