Question

What is the equilibrium constant expression for the reaction: N2 (g) + 3H2 (g) ⇌ 2NH3 (g) If the equilibrium concentrations of N2, H2, and NH3 are 0.25 M, 0.08 M, and 0.40 M, respectively, what is the numerical value of the equilibrium constant Kc?

Answer 1

The equilibrium constant expression for the given reaction is:Kc = [NH3]^2 /  [N2] * [H2]^3 Given the equilibrium concentrations of N2, H2, and NH3 are 0.25 M, 0.08 M, and 0.40 M, respectively, we can plug these values into the expression:Kc =  0.40 ^2 /  0.25 *  0.08 ^3 Kc = 0.16 /  0.25 * 0.000512 Kc = 0.16 / 0.000128Kc  1250So, the numerical value of the equilibrium constant Kc is approximately 1250.