0 votes
21 views
ago in Physical Chemistry by (139k points)
What is the equilibrium constant expression for the following reaction at 298 K?H2(g) + I2(g) ⇌ 2HI(g)

1 Answer

0 votes
ago by (10 points)
The equilibrium constant expression for a reaction is given by the ratio of the concentrations of the products raised to their stoichiometric coefficients divided by the concentrations of the reactants raised to their stoichiometric coefficients.For the given reaction:H2 g  + I2 g   2HI g The equilibrium constant expression  Kc  can be written as:Kc = [HI]^2 /  [H2] * [I2] Where [HI], [H2], and [I2] represent the equilibrium concentrations of HI, H2, and I2, respectively.

Related questions

Welcome to Sarvan Science Q&A, where you can ask questions and receive answers from other members of the community.
...