Question

Determine the equilibrium constant (Kc) for the following reaction at a temperature of 298 K if the concentrations of reactants and products are [CO] = 0.10 M, [H2] = 0.20 M, and [CH3OH] = 0.05 M:CO(g) + 2H2(g) ↔ CH3OH(g)

Answer 1

To determine the equilibrium constant  Kc  for the given reaction, we need to use the formula:Kc = [Products] / [Reactants]For the given reaction:CO g  + 2H2 g   CH3OH g The equilibrium constant expression is:Kc = [CH3OH] /  [CO] * [H2]^2 Now, we can plug in the given concentrations:Kc = [0.05] /  0.10 *  0.20 ^2 Kc = 0.05 /  0.10 * 0.04 Kc = 0.05 / 0.004Kc = 12.5The equilibrium constant  Kc  for the given reaction at 298 K is 12.5.