The balanced chemical equation for the reaction between hydrochloric acid HCl and sodium hydroxide NaOH is:HCl aq + NaOH aq NaCl aq + H2O l To find the moles of sodium chloride NaCl produced, we first need to determine the moles of hydrochloric acid HCl in the 50 mL of 0.1 M solution:moles of HCl = volume in L molarity moles of HCl = 50 mL 1 L / 1000 mL 0.1 Mmoles of HCl = 0.005 molesSince the reaction between HCl and NaOH is a 1:1 ratio, the moles of NaCl produced will be equal to the moles of HCl reacted:moles of NaCl = moles of HClmoles of NaCl = 0.005 molesSo, 0.005 moles of sodium chloride NaCl will be produced when 50 mL of 0.1 M HCl is reacted with excess NaOH.