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What is the total number of electrons transferred in the following electrochemical reaction: 2Fe3+ (aq) + Mg (s) → 2Fe2+ (aq) + Mg2+ (aq)?

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In the given electrochemical reaction:2Fe  aq  + Mg  s   2Fe  aq  + Mg  aq Each Fe ion is reduced to Fe, which means it gains one electron. Since there are two Fe ions, a total of 2 electrons are gained in the reduction half-reaction.Mg  s  is oxidized to Mg  aq , which means it loses two electrons.So, the total number of electrons transferred in this reaction is 2  from the reduction of Fe ions  + 2  from the oxidation of Mg  = 4 electrons.

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