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What is the magnetic moment of Fe(CO)₅ in the gas phase? Calculate the magnetic moment and identify its configuration.

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Fe CO , also known as iron pentacarbonyl, is a complex molecule with an iron atom  Fe  surrounded by five carbonyl  CO  ligands. To determine the magnetic moment of Fe CO , we first need to identify the electron configuration of the central iron atom.Iron has an atomic number of 26, which means it has 26 electrons in its ground state. The electron configuration for iron is [Ar] 3d^6 4s^2. However, in Fe CO , the iron atom is in a lower oxidation state due to the presence of the carbonyl ligands. The electron configuration of Fe in Fe CO  is [Ar] 3d^8, as it loses the 4s electrons and gains two electrons from the carbonyl ligands.Now, we can calculate the magnetic moment    using the formula: =  n n+2  where n is the number of unpaired electrons. In the 3d^8 configuration, there are two unpaired electrons. Therefore, we can plug this value into the formula: =  2 2+2   =  2 4   = 8The magnetic moment of Fe CO  in the gas phase is 8 Bohr magnetons.The electron configuration of Fe CO  is [Ar] 3d^8, with two unpaired electrons in the 3d orbitals.
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