To calculate the magnetic moment of Fe CO using Molecular Orbital Theory, we first need to determine the electron configuration of the complex.Fe CO is an octahedral complex with Fe as the central metal atom and CO as the ligands. The oxidation state of Fe in this complex is 0, and its electron configuration is [Ar] 3d^6 4s^2.CO is a strong field ligand, and it causes the pairing of electrons in the d orbitals of Fe. The Molecular Orbital Theory for octahedral complexes involves the splitting of the d orbitals into two sets: tg lower energy and e_g higher energy . In the presence of strong field ligands, the electrons in the d orbitals will pair up in the lower energy tg orbitals.The electron configuration of Fe in Fe CO will be:tg^6 e_g^0Since all the electrons are paired, there are no unpaired electrons in the complex. The magnetic moment can be calculated using the formula: = n n+2 where n is the number of unpaired electrons.In this case, n = 0, so the magnetic moment of Fe CO is: = 0 0+2 = 0Therefore, the magnetic moment of Fe CO is 0, indicating that the complex is diamagnetic.