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For the reaction below, calculate the equilibrium constant (K) when the electrode potentials are E°(Cu2+/Cu) = +0.34 V and E°(Ag+/Ag) = +0.80 V:Cu(s) + 2Ag+(aq) → Cu2+(aq) + 2Ag(s)

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ago by (690 points)
To calculate the equilibrium constant  K  for the given reaction, we first need to determine the standard cell potential  Ecell  for the reaction. The cell potential can be calculated using the Nernst equation:Ecell = E cathode  - E anode In this case, the Cu2+/Cu half-cell acts as the anode  oxidation  and the Ag+/Ag half-cell acts as the cathode  reduction . Therefore, we can plug in the given electrode potentials:Ecell = E Ag+/Ag  - E Cu2+/Cu  = 0.80 V - 0.34 V = 0.46 VNow that we have the standard cell potential, we can calculate the equilibrium constant  K  using the relationship between Ecell and the Gibbs free energy change  G :G = -nFEcellWhere n is the number of moles of electrons transferred in the reaction  in this case, n = 2 , F is the Faraday constant  96,485 C/mol , and G is the standard Gibbs free energy change.We can also relate the Gibbs free energy change to the equilibrium constant  K  using the following equation:G = -RTln K Where R is the gas constant  8.314 J/molK  and T is the temperature in Kelvin  assuming 298 K for standard conditions .By combining these two equations, we can solve for K:-RTln K  = -nFEcellln K  =  nFEcell  / RTK = e^ nFEcell  / RT Plugging in the values:K = e^ 2 * 96485 * 0.46  /  8.314 * 298  K  1.1  10^10Therefore, the equilibrium constant  K  for the given reaction is approximately 1.1  10^10.

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