To calculate the standard electrode potential for the given reaction, we need to determine the oxidation and reduction half-reactions. In this case, Cu is being oxidized and Ag+ is being reduced.The oxidation half-reaction is:Cu s Cu2+ aq + 2e-The reduction half-reaction is:2Ag+ aq + 2e- 2Ag s Now, we need to reverse the oxidation half-reaction to match the given standard reduction potential for Cu2+ + 2e- Cu:Cu2+ aq + 2e- Cu s The standard reduction potential for this reversed reaction is -0.34 V since we reversed the reaction, we need to change the sign .Now, we can add the standard reduction potentials of the two half-reactions to get the overall standard electrode potential for the given reaction:E cell = E reduction + E oxidation E cell = 0.80 V + -0.34 V E cell = 0.46 VSo, the standard electrode potential for the given reaction is 0.46 V.